2j^3-2j^2-12j=0

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Solution for 2j^3-2j^2-12j=0 equation:


Simplifying
2j3 + -2j2 + -12j = 0

Reorder the terms:
-12j + -2j2 + 2j3 = 0

Solving
-12j + -2j2 + 2j3 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '2j'.
2j(-6 + -1j + j2) = 0

Factor a trinomial.
2j((-2 + -1j)(3 + -1j)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor 'j' equal to zero and attempt to solve: Simplifying j = 0 Solving j = 0 Move all terms containing j to the left, all other terms to the right. Simplifying j = 0

Subproblem 2

Set the factor '(-2 + -1j)' equal to zero and attempt to solve: Simplifying -2 + -1j = 0 Solving -2 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1j = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1j = 0 + 2 -1j = 0 + 2 Combine like terms: 0 + 2 = 2 -1j = 2 Divide each side by '-1'. j = -2 Simplifying j = -2

Subproblem 3

Set the factor '(3 + -1j)' equal to zero and attempt to solve: Simplifying 3 + -1j = 0 Solving 3 + -1j = 0 Move all terms containing j to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1j = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1j = 0 + -3 -1j = 0 + -3 Combine like terms: 0 + -3 = -3 -1j = -3 Divide each side by '-1'. j = 3 Simplifying j = 3

Solution

j = {0, -2, 3}

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